what volume of a 2.5 m lithium nitrate solution would be needed to make 150 ml of a 1.0 m solution by…

what volume of a 2.5 m lithium nitrate solution would be needed to make 150 ml of a 1.0 m solution by dilution?\nm₁ = 2.5 m v₁ = ? ml\nm₂ = 1.0 m v₂ = 150 ml\nm₁v₁ = m₂v₂\n? ml lino₃

what volume of a 2.5 m lithium nitrate solution would be needed to make 150 ml of a 1.0 m solution by dilution?\nm₁ = 2.5 m v₁ = ? ml\nm₂ = 1.0 m v₂ = 150 ml\nm₁v₁ = m₂v₂\n? ml lino₃

Answer

Explanation:

Step1: Recall Dilution Formula

The formula for dilution is ( M_1V_1 = M_2V_2 ), where ( M_1 ) is the initial molarity, ( V_1 ) is the initial volume, ( M_2 ) is the final molarity, and ( V_2 ) is the final volume.

Step2: Rearrange for ( V_1 )

We need to solve for ( V_1 ), so rearrange the formula: ( V_1=\frac{M_2V_2}{M_1} ).

Step3: Substitute Values

Substitute ( M_1 = 2.5\ M ), ( M_2 = 1.0\ M ), and ( V_2 = 150\ mL ) into the formula: ( V_1=\frac{1.0\ M\times150\ mL}{2.5\ M} ).

Step4: Calculate

First, multiply ( 1.0\ M ) and ( 150\ mL ) to get ( 150\ M\cdot mL ). Then divide by ( 2.5\ M ): ( \frac{150\ M\cdot mL}{2.5\ M}=60\ mL ).

Answer:

60