as water is added to a 0.10 m nacl aqueous solution, the conductivity of the resulting solution\nincreases…

as water is added to a 0.10 m nacl aqueous solution, the conductivity of the resulting solution\nincreases, but the concentration of ions remains the same\nincreases because the concentration of ions decreases\ndecreases, but the concentration of ions remains the same\ndecreases because the concentration of ions decreases

as water is added to a 0.10 m nacl aqueous solution, the conductivity of the resulting solution\nincreases, but the concentration of ions remains the same\nincreases because the concentration of ions decreases\ndecreases, but the concentration of ions remains the same\ndecreases because the concentration of ions decreases

Answer

Explanation:

Step1: 明确溶液导电性与离子浓度关系

溶液导电性与离子浓度和离子所带电荷等有关，在离子所带电荷等条件不变时，离子浓度越高，导电性越强。

Step2: 分析加水后氯化钠溶液情况

向$0.10\ M$的$NaCl$水溶液中加水，溶液被稀释，$NaCl$完全电离出的$Na^+$和$Cl^-$物质的量不变，但溶液体积增大，根据$c = \frac{n}{V}$（$c$为物质的量浓度，$n$为溶质物质的量，$V$为溶液体积），离子浓度减小。

Step3: 确定导电性变化

因为离子浓度减小，所以溶液导电性降低。

Answer:

decreases because the concentration of ions decreases