we wish to determine how many grams of kno₃ can form when 100. ml of 0.40 m k₂cro₄ solution is added to…

we wish to determine how many grams of kno₃ can form when 100. ml of 0.40 m k₂cro₄ solution is added to excess agno₃.\n2agno₃(aq) + k₂cro₄(aq) → ag₂cro₄(s) + 2kno₃(aq)\nhow many moles of k₂cro₄ are present in 100. ml of 0.40 m k₂cro₄?

we wish to determine how many grams of kno₃ can form when 100. ml of 0.40 m k₂cro₄ solution is added to excess agno₃.\n2agno₃(aq) + k₂cro₄(aq) → ag₂cro₄(s) + 2kno₃(aq)\nhow many moles of k₂cro₄ are present in 100. ml of 0.40 m k₂cro₄?

Answer

Explanation:

Step1: Recall molarity formula

The molarity formula is $M=\frac{n}{V}$, where $M$ is molarity, $n$ is the number of moles, and $V$ is the volume in liters. First, convert the volume from mL to L. Since $1\ L = 1000\ mL$, then $V = 100\ mL=0.1\ L$ and $M = 0.40\ M$.

Step2: Rearrange formula to solve for moles

Rearranging $M=\frac{n}{V}$ for $n$ gives $n = M\times V$. Substitute $M = 0.40\ mol/L$ and $V=0.1\ L$ into the formula: $n=0.40\ mol/L\times0.1\ L$.

Answer:

$0.04\ mol$