we wish to determine the mass of mg required to react completely with 250 ml of 1.0 m hcl.\nhcl reacts with…

we wish to determine the mass of mg required to react completely with 250 ml of 1.0 m hcl.\nhcl reacts with mg according to the equation below.\n2hcl(aq) + mg(s) → mgcl₂(aq) + h₂(g)\nhow many moles of hcl are present in 250. ml of 1.0 m hcl?

we wish to determine the mass of mg required to react completely with 250 ml of 1.0 m hcl.\nhcl reacts with mg according to the equation below.\n2hcl(aq) + mg(s) → mgcl₂(aq) + h₂(g)\nhow many moles of hcl are present in 250. ml of 1.0 m hcl?

Answer

Explanation:

Step1: Recall molarity formula

The formula for molarity $M=\frac{n}{V}$, where $M$ is molarity, $n$ is the number of moles, and $V$ is the volume in liters. We need to convert the volume of HCl from mL to L. Given $V = 250\ mL=0.250\ L$ and $M = 1.0\ M$.

Step2: Rearrange formula to find moles

Rearranging the molarity formula $n = M\times V$. Substitute $M = 1.0\ mol/L$ and $V=0.250\ L$ into the formula. $n=1.0\ mol/L\times0.250\ L$

Answer:

$0.250$ moles