we wish to determine the moles of mg(oh)₂ produced when 250 ml of 2.0 m koh reacts with excess mg(no₃)₂…

we wish to determine the moles of mg(oh)₂ produced when 250 ml of 2.0 m koh reacts with excess mg(no₃)₂. mg(no₃)₂(aq) + 2koh(aq) → 2kno₃(aq) + mg(oh)₂(s) how many moles of koh are present in 250 ml of 2.0 m koh?

we wish to determine the moles of mg(oh)₂ produced when 250 ml of 2.0 m koh reacts with excess mg(no₃)₂. mg(no₃)₂(aq) + 2koh(aq) → 2kno₃(aq) + mg(oh)₂(s) how many moles of koh are present in 250 ml of 2.0 m koh?

Answer

Explanation:

Step1: Recall the formula for moles from molarity

The formula relating moles ((n)), molarity ((M)) and volume ((V) in liters) is (n = M\times V).

Step2: Convert volume to liters

Given volume (V = 250\space mL). Since (1\space L = 1000\space mL), we convert (250\space mL) to liters: (V=\frac{250}{1000}=0.25\space L).

Step3: Calculate moles of KOH

Molarity (M = 2.0\space M) (or (2.0\space mol/L)) and (V = 0.25\space L). Using the formula (n = M\times V), we substitute the values: (n=2.0\space mol/L\times0.25\space L = 0.5\space mol).

Answer:

(0.5) moles