write a balanced chemical equation for the standard formation reaction of solid magnesium bromide (mgbr₂).
write a balanced chemical equation for the standard formation reaction of solid magnesium bromide (mgbr₂).
Answer
Explanation:
Step1: Identify reactants
Magnesium (Mg) is a solid and bromine exists as $Br_2$ (a liquid at standard - conditions). $Mg(s)+Br_2(l)\rightarrow$
Step2: Determine product
The product is magnesium bromide ($MgBr_2$), which is solid at standard - conditions. $Mg(s)+Br_2(l)\rightarrow MgBr_2(s)$
Step3: Check balance
On the left - hand side, we have 1 Mg atom and 2 Br atoms. On the right - hand side, we have 1 Mg atom and 2 Br atoms. The equation is already balanced.
Answer:
$Mg(s)+Br_2(l)\rightarrow MgBr_2(s)$