write a balanced chemical equation for the standard formation reaction of solid iron(ii) cyanide (fe(cn)₂).
write a balanced chemical equation for the standard formation reaction of solid iron(ii) cyanide (fe(cn)₂).
Answer
Explanation:
Step1: Identify elements in compound
The elements in $Fe(CN)_2$ are iron (Fe), carbon (C), and nitrogen (N).
Step2: Write reactants in standard - state
The standard - state of iron is solid (Fe(s)), carbon is solid (C(s)), and nitrogen is a diatomic gas ($N_2$(g)).
Step3: Balance the equation
We need 1 mole of Fe, 2 moles of C, and 1 mole of $N_2$ to form 1 mole of $Fe(CN)_2$(s). The balanced chemical equation for the standard formation reaction is: $Fe(s)+2C(s) + N_2(g)=Fe(CN)_2(s)$
Answer:
$Fe(s)+2C(s) + N_2(g)=Fe(CN)_2(s)$