write a balanced nuclear equation for the decay of strontium - 83 by positron emission.
write a balanced nuclear equation for the decay of strontium - 83 by positron emission.
Answer
Explanation:
Step1: Identify strontium - 83
Strontium has an atomic number of 38. So strontium - 83 is written as $^{83}_{38}Sr$.
Step2: Recall positron emission
In positron emission, a proton in the nucleus is converted into a neutron and a positron. The positron is represented as $^{0}_{+1}e$. The mass number remains the same and the atomic number decreases by 1.
Step3: Determine the daughter nucleus
The new atomic number is $38 - 1=37$, which is rubidium (Rb). The mass number is 83. So the daughter nucleus is $^{83}_{37}Rb$.
Step4: Write the nuclear equation
The balanced nuclear equation is $^{83}{38}Sr\rightarrow^{83}{37}Rb + ^{0}_{+1}e$.
Answer:
$^{83}{38}Sr\rightarrow^{83}{37}Rb + ^{0}_{+1}e$