if you have 1 mol xe and 1 mol f₂, how many moles of xef₄ can you create in the following chemical reaction…

if you have 1 mol xe and 1 mol f₂, how many moles of xef₄ can you create in the following chemical reaction? xe (g) + 2 f₂ (g) → xef₄ (g)\na 2 mol\nb 1 mol\nc 0.5 mol\nd 0.25 mol

if you have 1 mol xe and 1 mol f₂, how many moles of xef₄ can you create in the following chemical reaction? xe (g) + 2 f₂ (g) → xef₄ (g)\na 2 mol\nb 1 mol\nc 0.5 mol\nd 0.25 mol

Answer

Answer:

C. 0.5 mol

Explanation:

Step1: Identify limiting reactant

From the reaction $Xe(g)+2F_2(g)\rightarrow XeF_4(g)$, the mole - ratio of $Xe$ to $F_2$ is 1:2. Given 1 mol $Xe$ and 1 mol $F_2$. For 1 mol $Xe$, we need 2 mol $F_2$ for complete reaction. Since we have only 1 mol $F_2$, $F_2$ is the limiting reactant.

Step2: Calculate moles of $XeF_4$

The mole - ratio of $F_2$ to $XeF_4$ is 2:1. Using the formula $n_{XeF_4}=\frac{n_{F_2}}{2}$. Substituting $n_{F_2} = 1$ mol, we get $n_{XeF_4}=\frac{1}{2}=0.5$ mol.