you want to determine the volume of 2.5 m lithium nitrate solution needed to make 150 ml of a 1.0 m…
you want to determine the volume of 2.5 m lithium nitrate solution needed to make 150 ml of a 1.0 m solution. what is v₁ (volume of the concentrated solution) for this dilution? the unknown 1.0 m lino₃ 150 ml
Answer
Explanation:
Step1: Recall Dilution Formula
The dilution formula is ( M_1V_1 = M_2V_2 ), where ( M_1 ) is the molarity of the concentrated solution, ( V_1 ) is its volume, ( M_2 ) is the molarity of the diluted solution, and ( V_2 ) is its volume.
Step2: Identify Known Values
We know ( M_1 = 2.5 , M ), ( M_2 = 1.0 , M ), ( V_2 = 150 , \text{mL} ), and we need to find ( V_1 ).
Step3: Rearrange Formula for ( V_1 )
Rearrange ( M_1V_1 = M_2V_2 ) to solve for ( V_1 ): ( V_1 = \frac{M_2V_2}{M_1} ).
Step4: Substitute Values
Substitute ( M_2 = 1.0 , M ), ( V_2 = 150 , \text{mL} ), and ( M_1 = 2.5 , M ) into the formula: ( V_1 = \frac{1.0 , M \times 150 , \text{mL}}{2.5 , M} ).
Step5: Calculate ( V_1 )
Simplify the expression: ( V_1 = \frac{150}{2.5} = 60 , \text{mL} ).
Answer:
( 60 , \text{mL} )