the yttrium - 88 nuclide radioactively decays by electron capture. write a balanced nuclear chemical…

Explanation:

Step1: Identify the parent nuclide

Yttrium - 88 has atomic number 39 and mass number 88, written as $_{39}^{88}Y$.

Step2: Understand electron - capture process

In electron - capture, an inner - shell electron (usually a K - or L - shell electron) is captured by the nucleus. The electron has a mass number of 0 and a charge of - 1, written as $_{ - 1}^{0}e$.

Step3: Determine the product nuclide

When an electron is captured by a proton in the nucleus, a proton is converted into a neutron. The atomic number decreases by 1 and the mass number remains the same. The new element has atomic number 38 (strontium, Sr) and mass number 88. Also, a neutrino ($\nu$) is emitted. The balanced nuclear chemical equation is ${39}^{88}Y+{ - 1}^{0}e\rightarrow_{38}^{88}Sr+\nu$.

Answer:

${39}^{88}Y+{ - 1}^{0}e\rightarrow_{38}^{88}Sr+\nu$