3. zn + 2cucl → zncl₂ + 2cu\n?g 97.1g

Answer:

$32.7$ g

Explanation:

Step1: Calculate molar mass of $CuCl$

The molar - mass of $Cu$ is $63.5$ g/mol and of $Cl$ is $35.5$ g/mol. So, $M_{CuCl}=63.5 + 35.5=99$ g/mol.

Step2: Calculate moles of $CuCl$

$n_{CuCl}=\frac{m_{CuCl}}{M_{CuCl}}=\frac{97.1}{99}\approx0.981$ mol.

Step3: Determine mole - ratio from the balanced equation

From the balanced equation $Zn + 2CuCl\rightarrow ZnCl_2+2Cu$, the mole - ratio of $Zn$ to $CuCl$ is $n_{Zn}:n_{CuCl}=1:2$.

Step4: Calculate moles of $Zn$

$n_{Zn}=\frac{1}{2}n_{CuCl}=\frac{1}{2}\times0.981 = 0.4905$ mol.

Step5: Calculate mass of $Zn$

The molar mass of $Zn$ is $65.4$ g/mol. So, $m_{Zn}=n_{Zn}\times M_{Zn}=0.4905\times65.4 = 32.7$ g.