zn + 2hcl → zncl₂ + h₂\nzn: 65.38 g/mol\na 3.79 l container can hold 0.15 moles h₂ gas. what mass of zn is…

zn + 2hcl → zncl₂ + h₂\nzn: 65.38 g/mol\na 3.79 l container can hold 0.15 moles h₂ gas. what mass of zn is required to generate 0.15 mol h₂?\n? g zn\nhint: use stoichiometry.

zn + 2hcl → zncl₂ + h₂\nzn: 65.38 g/mol\na 3.79 l container can hold 0.15 moles h₂ gas. what mass of zn is required to generate 0.15 mol h₂?\n? g zn\nhint: use stoichiometry.

Answer

Explanation:

Step1: Determine mole - ratio from chemical equation

From $Zn + 2HCl\rightarrow ZnCl_2 + H_2$, the mole - ratio of $Zn$ to $H_2$ is $1:1$.

Step2: Calculate moles of Zn

Since the mole - ratio of $Zn$ to $H_2$ is $1:1$, if $n(H_2)=0.15$ mol, then $n(Zn) = 0.15$ mol.

Step3: Calculate mass of Zn

The molar mass of $Zn$ is $M(Zn)=65.38$ g/mol. Using the formula $m = n\times M$, we have $m(Zn)=n(Zn)\times M(Zn)$. Substituting $n(Zn) = 0.15$ mol and $M(Zn)=65.38$ g/mol, we get $m(Zn)=0.15\times65.38$ g. $m(Zn)=9.807$ g

Answer:

$9.81$ g (rounded to two decimal places)