2. (02.01 lc)\nfor a certain industry, the mean annual salary rose from $59,760 to $63,390. calculate the…

2. (02.01 lc)\nfor a certain industry, the mean annual salary rose from $59,760 to $63,390. calculate the percent of increase. round to the nearest tenth. (2 points)\n6.1%\n6.0%\n6.2%\n5.7%\n\n3. (02.01 mc)\nthe median weekly income for someone with a high school diploma was $678.00. if they continued their education and obtained a bachelors degree, their median weekly income increased about 67.7%. determine the median weekly income for someone with a bachelors degree. (2 points)\n$799.45\n$568.51\n$218.99\n$1,137.01
Answer
Explanation:
Step1: Calculate the amount of increase for the first - part
The formula for the amount of increase is $\text{Increase}=\text{New Value}-\text{Original Value}$. For the mean annual salary problem, the original value is $59760$ and the new value is $63390$. So, $\text{Increase}=63390 - 59760=3630$.
Step2: Calculate the percent of increase for the first - part
The formula for percent of increase is $\text{Percent Increase}=\frac{\text{Increase}}{\text{Original Value}}\times100%$. Substitute the values: $\text{Percent Increase}=\frac{3630}{59760}\times 100%\approx 6.1%$.
Step3: Calculate the median weekly income for the second - part
The formula for finding the new value when there is a percentage increase is $\text{New Value}=\text{Original Value}\times(1 + \text{Percent Increase as a decimal})$. The original median weekly income for a high - school graduate is $678$ and the percent increase is $67.7%=0.677$. So, $\text{New Value}=678\times(1 + 0.677)=678\times1.677 = 1137.006\approx1137.01$.
Answer:
- A. $6.1%$
- D. $$1,137.01$