13) first national bank is offering 4.25% interest on an account. susan makes an initial deposit of $20,000…

13) first national bank is offering 4.25% interest on an account. susan makes an initial deposit of $20,000. calculate the interest earned over 20 years if the bank... a) calculates the interest using simple interest (i = prt). b) calculates the interest using compound interest compounded annually. c) calculates the interest using compound interest compounded quarterly. d) calculates the interest using compound interest compounded monthly.

13) first national bank is offering 4.25% interest on an account. susan makes an initial deposit of $20,000. calculate the interest earned over 20 years if the bank... a) calculates the interest using simple interest (i = prt). b) calculates the interest using compound interest compounded annually. c) calculates the interest using compound interest compounded quarterly. d) calculates the interest using compound interest compounded monthly.

Answer

Explanation:

Step1: Identify values for simple - interest

Principal $P = 20000$, rate $r=0.0425$ (since $4.25%=0.0425$), time $t = 20$. Using the simple - interest formula $I=Prt$. $I=20000\times0.0425\times20$

Step2: Calculate simple - interest

$I = 20000\times0.0425\times20=17000$

Step3: Identify values for compound - interest (annually)

$P = 20000$, $r = 0.0425$, $n = 1$ (compounded annually), $t=20$. The compound - interest formula is $A=P(1 +\frac{r}{n})^{nt}$, and $I=A - P$. $A=20000(1+\frac{0.0425}{1})^{1\times20}=20000(1.0425)^{20}$ $A\approx20000\times2.20804\approx44160.8$ $I=A - P=44160.8 - 20000=24160.8$

Step4: Identify values for compound - interest (quarterly)

$P = 20000$, $r = 0.0425$, $n = 4$ (compounded quarterly), $t = 20$. $A=20000(1+\frac{0.0425}{4})^{4\times20}=20000(1 + 0.010625)^{80}$ $A\approx20000\times2.22107\approx44421.4$ $I=A - P=44421.4-20000 = 24421.4$

Step5: Identify values for compound - interest (monthly)

$P = 20000$, $r = 0.0425$, $n = 12$ (compounded monthly), $t = 20$. $A=20000(1+\frac{0.0425}{12})^{12\times20}=20000(1+\frac{0.0425}{12})^{240}$ $A\approx20000\times2.22497\approx44499.4$ $I=A - P=44499.4 - 20000=24499.4$

Answer:

a) The simple interest is $17000$. b) The compound interest compounded annually is approximately $24160.8$. c) The compound interest compounded quarterly is approximately $24421.4$. d) The compound interest compounded monthly is approximately $24499.4$.