if $550 are deposited into an account with 9% interest rate, compounded monthly, what is the balance after 6…

if $550 are deposited into an account with 9% interest rate, compounded monthly, what is the balance after 6 years? next, enter r, or the interest rate as a decimal. r = ?
Answer
Explanation:
Step1: Identify compound - interest formula
The compound - interest formula is $A = P(1+\frac{r}{n})^{nt}$, where $A$ is the final amount, $P$ is the principal amount, $r$ is the annual interest rate (in decimal), $n$ is the number of times interest is compounded per year, and $t$ is the number of years. Given $P = 550$, $r=0.09$ (since $9%=0.09$), $n = 12$ (compounded monthly), and $t = 6$.
Step2: Substitute values into the formula
$A=550(1 +\frac{0.09}{12})^{12\times6}$ First, calculate the value inside the parentheses: $\frac{0.09}{12}=0.0075$, then $1+\frac{0.09}{12}=1 + 0.0075=1.0075$. Next, calculate the exponent: $12\times6 = 72$. So, $A = 550\times(1.0075)^{72}$.
Step3: Calculate $(1.0075)^{72}$
Using a calculator, $(1.0075)^{72}\approx1.71147$.
Step4: Calculate the final amount $A$
$A=550\times1.71147\approx941.31$.
Answer:
$$941.31$