arturo invested $630 in an account paying an interest rate of 4.3% compounded continuously. assuming no…

arturo invested $630 in an account paying an interest rate of 4.3% compounded continuously. assuming no deposits or withdrawals are made, how much money, to the nearest ten dollars, would be in the account after 9 years?
Answer
Explanation:
Step1: Recall continuous - compounding formula
The formula for continuous - compounding is $A = Pe^{rt}$, where $A$ is the amount of money in the account after $t$ years, $P$ is the principal amount (initial investment), $r$ is the annual interest rate (in decimal form), and $t$ is the number of years.
Step2: Convert the interest rate to decimal
Given $r = 4.3%=0.043$, $P = 630$, and $t = 9$.
Step3: Substitute values into the formula
$A=630\times e^{0.043\times9}$. First, calculate the exponent: $0.043\times9 = 0.387$. Then, find $e^{0.387}$. Using a calculator, $e^{0.387}\approx1.472$. So, $A = 630\times1.472$. $A=630\times1.472 = 927.36$.
Step4: Round to the nearest ten dollars
Rounding $927.36$ to the nearest ten dollars, we look at the digit in the ones place. Since $7\geq5$, we round up. So, $A\approx930$.
Answer:
$930$