cooper wants to start a business, which he estimates will cost $7,248.00. if cooper puts $2,000.00 into a…

cooper wants to start a business, which he estimates will cost $7,248.00. if cooper puts $2,000.00 into a savings account which earns 14% interest compounded continuously, how long will it be until he has enough money to start the business? round your answer to the nearest month. years and months

cooper wants to start a business, which he estimates will cost $7,248.00. if cooper puts $2,000.00 into a savings account which earns 14% interest compounded continuously, how long will it be until he has enough money to start the business? round your answer to the nearest month. years and months

Answer

Explanation:

Step1: Recall continuous - compounding formula

The formula for continuous - compounding is $A = Pe^{rt}$, where $A$ is the final amount, $P$ is the principal amount, $r$ is the annual interest rate (in decimal form), and $t$ is the time in years. We know that $A=$7248$, $P = $2000$, and $r=0.14$. Substitute these values into the formula: $7248 = 2000e^{0.14t}$.

Step2: Solve for $t$

First, divide both sides of the equation by 2000: $\frac{7248}{2000}=e^{0.14t}$. So, $3.624 = e^{0.14t}$. Then, take the natural logarithm of both sides: $\ln(3.624)=\ln(e^{0.14t})$. Since $\ln(e^{x}) = x$, we have $\ln(3.624)=0.14t$. Now, solve for $t$: $t=\frac{\ln(3.624)}{0.14}$. We know that $\ln(3.624)\approx1.285$ and $t=\frac{1.285}{0.14}\approx9.179$ years.

Step3: Convert years to years and months

The whole - number part of $t$ is the number of years, which is 9 years. The decimal part $0.179$ of a year is converted to months. Since there are 12 months in a year, the number of months is $0.179\times12\approx2.15$. Rounding to the nearest month, we get 2 months.

Answer:

9 years and 2 months