the cost per ton, y, to build an oil tanker of x thousand deadweight tons was approximated by…

the cost per ton, y, to build an oil tanker of x thousand deadweight tons was approximated by c(x)=\frac{225000}{x + 465} for x>0. a. find c(25), c(50), c(100), c(200), c(300), and c(400). c(25) = c(50) = c(100) = c(200) = c(300) = c(400) = (type an integer or decimal rounded to one decimal place as needed.)

the cost per ton, y, to build an oil tanker of x thousand deadweight tons was approximated by c(x)=\frac{225000}{x + 465} for x>0. a. find c(25), c(50), c(100), c(200), c(300), and c(400). c(25) = c(50) = c(100) = c(200) = c(300) = c(400) = (type an integer or decimal rounded to one decimal place as needed.)

Answer

Explanation:

Step1: Calculate C(25)

Substitute $x = 25$ into $C(x)=\frac{225000}{x + 465}$: $C(25)=\frac{225000}{25+465}=\frac{225000}{490}\approx459.2$

Step2: Calculate C(50)

Substitute $x = 50$ into $C(x)=\frac{225000}{x + 465}$: $C(50)=\frac{225000}{50 + 465}=\frac{225000}{515}\approx436.9$

Step3: Calculate C(100)

Substitute $x = 100$ into $C(x)=\frac{225000}{x + 465}$: $C(100)=\frac{225000}{100+465}=\frac{225000}{565}\approx398.2$

Step4: Calculate C(200)

Substitute $x = 200$ into $C(x)=\frac{225000}{x + 465}$: $C(200)=\frac{225000}{200+465}=\frac{225000}{665}\approx338.4$

Step5: Calculate C(300)

Substitute $x = 300$ into $C(x)=\frac{225000}{x + 465}$: $C(300)=\frac{225000}{300+465}=\frac{225000}{765}\approx294.1$

Step6: Calculate C(400)

Substitute $x = 400$ into $C(x)=\frac{225000}{x + 465}$: $C(400)=\frac{225000}{400+465}=\frac{225000}{865}\approx260.1$

Answer:

$C(25)\approx459.2$ $C(50)\approx436.9$ $C(100)\approx398.2$ $C(200)\approx338.4$ $C(300)\approx294.1$ $C(400)\approx260.1$