dante borrowed $8000 at a rate of 19.5%, compounded semiannually. assuming he makes no payments, how much…

dante borrowed $8000 at a rate of 19.5%, compounded semiannually. assuming he makes no payments, how much will he owe after 10 years? do not round any intermediate computations, and round your answer to the nearest cent.
Answer
Explanation:
Step1: Identify compound - interest formula
The compound - interest formula is $A = P(1+\frac{r}{n})^{nt}$, where $A$ is the amount of money accumulated after $n$ years, including interest, $P$ is the principal amount (the initial amount of money), $r$ is the annual interest rate (in decimal form), $n$ is the number of times that interest is compounded per year, and $t$ is the time the money is invested or borrowed for in years.
Step2: Convert given values to correct form
We have $P=$8000$, $r = 0.195$ (since $19.5%=0.195$), $n = 2$ (compounded semiannually), and $t = 10$ years.
Step3: Substitute values into formula
$A=8000(1 +\frac{0.195}{2})^{2\times10}=8000(1 + 0.0975)^{20}$.
Step4: Calculate the value inside the parentheses
$1+0.0975 = 1.0975$.
Step5: Calculate the exponentiation
$(1.0975)^{20}\approx6.08108$.
Step6: Calculate the final amount
$A = 8000\times6.08108=$48648.64$.
Answer:
$48648.64$