the dollar value v(t) of a certain car model that is t years old is given by the following exponential…

the dollar value v(t) of a certain car model that is t years old is given by the following exponential function. v(t)=24,500(0.86)^t find the value of the car after 6 years and after 12 years. round your answers to the nearest dollar as necessary. value after 6 years: $ value after 12 years: $
Answer
Explanation:
Step1: Substitute t = 6
Substitute (t = 6) into (v(t)=24500(0.86)^{t}), we get (v(6)=24500\times(0.86)^{6}).
Step2: Calculate (v(6))
((0.86)^{6}=0.86\times0.86\times0.86\times0.86\times0.86\times0.86\approx0.405), then (v(6)=24500\times0.405 = 9922.5\approx9923).
Step3: Substitute t = 12
Substitute (t = 12) into (v(t)=24500(0.86)^{t}), we get (v(12)=24500\times(0.86)^{12}).
Step4: Calculate (v(12))
((0.86)^{12}=(0.86^{6})^{2}\approx0.405^{2}= 0.164), then (v(12)=24500\times0.164 = 4018).
Answer:
Value after 6 years: $$9923$ Value after 12 years: $$4018$