sophia deposited $80,000 in a savings account with simple interest. two years later, she had earned $17,600…

sophia deposited $80,000 in a savings account with simple interest. two years later, she had earned $17,600 in interest. what was the interest rate? use the formula i = prt, where i is the interest earned, p is the principal (starting amount), r is the interest rate expressed as a decimal, and t is the time in years.

sophia deposited $80,000 in a savings account with simple interest. two years later, she had earned $17,600 in interest. what was the interest rate? use the formula i = prt, where i is the interest earned, p is the principal (starting amount), r is the interest rate expressed as a decimal, and t is the time in years.

Answer

Explanation:

Step1: Identify given values

$i = 17600$, $p=80000$, $t = 2$

Step2: Rearrange the formula for $r$

$r=\frac{i}{pt}$

Step3: Substitute values

$r=\frac{17600}{80000\times2}$ $r=\frac{17600}{160000}= 0.11$

Step4: Convert to percentage

$r = 0.11\times100%=11%$

Answer:

$11$