suppose a cost - benefit model is given by $y = \\frac{6.5x}{100 - x}$ where x is a number of percent and y…

suppose a cost - benefit model is given by $y = \\frac{6.5x}{100 - x}$ where x is a number of percent and y is the cost, in thousands of dollars, of removing x percent of a given pollutant. complete parts a through c. a. find the cost of removing each percent of pollutants: 50%; 70%; 80%; 90%; 95%; 98%; 99%. 50% $y = \\square$ 70% $y = \\square$ 80% $y = \\square$ 90% $y = \\square$ 95% $y = \\square$ 98% $y = \\square$ 99% $y = \\square$ (type an integer or decimal rounded to two decimal places as needed.)
Answer
Explanation:
Step1: Substitute x = 50 into the formula
$y=\frac{6.5\times50}{100 - 50}=\frac{325}{50}=6.50$
Step2: Substitute x = 70 into the formula
$y=\frac{6.5\times70}{100 - 70}=\frac{455}{30}\approx15.17$
Step3: Substitute x = 80 into the formula
$y=\frac{6.5\times80}{100 - 80}=\frac{520}{20}=26.00$
Step4: Substitute x = 90 into the formula
$y=\frac{6.5\times90}{100 - 90}=\frac{585}{10}=58.50$
Step5: Substitute x = 95 into the formula
$y=\frac{6.5\times95}{100 - 95}=\frac{617.5}{5}=123.50$
Step6: Substitute x = 98 into the formula
$y=\frac{6.5\times98}{100 - 98}=\frac{637}{2}=318.50$
Step7: Substitute x = 99 into the formula
$y=\frac{6.5\times99}{100 - 99}=\frac{643.5}{1}=643.50$
Answer:
50%: $y = 6.50$ 70%: $y\approx15.17$ 80%: $y = 26.00$ 90%: $y = 58.50$ 95%: $y = 123.50$ 98%: $y = 318.50$ 99%: $y = 643.50$