trevor has an investment worth $6,774.50. he made his only deposit in it 22 years ago. given that the…

trevor has an investment worth $6,774.50. he made his only deposit in it 22 years ago. given that the investment yields 2.7% simple interest annually, how big was the initial deposit?\na. $2,524.50\nb. $4,024.03\nc. $4,250.00\nd. $11,404.88

trevor has an investment worth $6,774.50. he made his only deposit in it 22 years ago. given that the investment yields 2.7% simple interest annually, how big was the initial deposit?\na. $2,524.50\nb. $4,024.03\nc. $4,250.00\nd. $11,404.88

Answer

Explanation:

Step1: Recall simple - interest formula

The formula for simple interest is $A = P(1 + rt)$, where $A$ is the final amount, $P$ is the principal (initial deposit), $r$ is the annual interest rate (in decimal form), and $t$ is the time in years.

We know that $A=$6774.50$, $r = 0.027$ (since $2.7%=0.027$), and $t = 22$ years.

Step2: Rearrange the formula to solve for $P$

Starting with $A = P(1+rt)$, we can solve for $P$ by dividing both sides of the equation by $(1 + rt)$. So $P=\frac{A}{1+rt}$.

Step3: Substitute the given values into the formula

Substitute $A = 6774.50$, $r=0.027$, and $t = 22$ into the formula:

$1+rt=1+(0.027\times22)=1 + 0.594=1.594$

$P=\frac{6774.50}{1.594}$

$P = 4250$

Answer:

c. $$4,250.00$