(01.04 mc) the green family is a family of six people. they have used 4,885.78 gallons of water so far this…

(01.04 mc) the green family is a family of six people. they have used 4,885.78 gallons of water so far this month. they cannot exceed 9,750.05 gallons per month during drought season. write an inequality to show how much water just one member of the family can use for the remainder of the month, assuming each family member uses the same amount of water every month. 6x - 4,885.78 ≤ 9,750.05 6x - 4,885.78 ≥ 9,750.05 6x + 4,885.78 ≤ 9,750.05 6x + 4,885.78 ≥ 9,750.05

(01.04 mc) the green family is a family of six people. they have used 4,885.78 gallons of water so far this month. they cannot exceed 9,750.05 gallons per month during drought season. write an inequality to show how much water just one member of the family can use for the remainder of the month, assuming each family member uses the same amount of water every month. 6x - 4,885.78 ≤ 9,750.05 6x - 4,885.78 ≥ 9,750.05 6x + 4,885.78 ≤ 9,750.05 6x + 4,885.78 ≥ 9,750.05

Answer

Explanation:

Step1: Define the variable

Let $x$ be the amount of water one - member can use for the remainder of the month.

Step2: Calculate the total remaining water for the family

Since there are 6 family members, the total amount of water the 6 members can use for the remainder of the month is $6x$.

Step3: Consider the total water used and the limit

The family has already used 4885.78 gallons, and the total water they can use in a month is 9750.05 gallons. So the sum of the water already used and the total water the 6 members can use for the remainder of the month must be less than or equal to the monthly limit. That is $6x + 4885.78\leq9750.05$.

Answer:

C. $6x + 4885.78\leq9750.05$