if $f(x)=16x - 30$ and $g(x)=14x - 6$, for which value of $x$ does $(f - g)(x)=0$?\n-18\n-12\n12\n18
if $f(x)=16x - 30$ and $g(x)=14x - 6$, for which value of $x$ does $(f - g)(x)=0$?\n-18\n-12\n12\n18
Answer
Answer:
C. 12
Explanation:
Step1: Find (f - g)(x)
$(f - g)(x)=f(x)-g(x)=(16x - 30)-(14x - 6)$
Step2: Simplify the expression
$(16x - 30)-(14x - 6)=16x-30 - 14x + 6=2x-24$
Step3: Set (f - g)(x) equal to 0 and solve for x
$2x-24 = 0$ $2x=24$ $x = 12$