21/41 graph y = (x - 3)^2 - 4

Explanation:

Step1: Identify the vertex form

The equation ( y=(x - 3)^2-4 ) is in vertex form ( y = a(x - h)^2 + k ), where ((h,k)) is the vertex. Here, ( h = 3 ), ( k=-4 ), so the vertex is ((3,-4)).

Step2: Identify the direction of opening

Since ( a = 1>0 ), the parabola opens upwards.

Step3: Check the graph

The graph should have a vertex at ((3,-4)) and open upwards. The given graph's vertex (the white dot) should be at ((3,-4)) and the parabola opens up, matching the equation.

Answer:

The graph (with vertex at (3, - 4) and opening upwards) correctly represents ( y=(x - 3)^2-4 ). (If choosing from the given graph, the parabola with vertex at (3, - 4) and opening up is the correct one, likely the middle - looking parabola around x = 3 with vertex at y=-4)