26 given $g(x)=x^{3}+2x^{2}-x$, evaluate $g(-3)$.

Explanation:

Step1: Substitute x = -3

$g(-3)=(-3)^{3}+2\times(-3)^{2}-(-3)$

Step2: Calculate each term

$(-3)^{3}=-27$, $2\times(-3)^{2}=2\times9 = 18$, $-(-3)=3$ So $g(-3)=-27 + 18+3$

Step3: Perform addition

$g(-3)=-27+21=-6$

Answer:

$-6$