27) g(x)=x^3 - 3x^2\nfind g(g(1))
27) g(x)=x^3 - 3x^2\nfind g(g(1))
Answer
Explanation:
Step1: Calculate g(1)
Substitute x = 1 into g(x): [ \begin{align*} g(1)&=1^{3}-3\times1^{2}\ &=1 - 3\ &=- 2 \end{align*} ]
Step2: Calculate g(g(1))
Since g(1)= - 2, substitute x=-2 into g(x): [ \begin{align*} g(g(1))&=g(-2)\ &=(-2)^{3}-3\times(-2)^{2}\ &=-8-3\times4\ &=-8 - 12\ &=-20 \end{align*} ]
Answer:
-20