3. $2sqrt3{x - 3}=4$

Answer:

$x = 11$

Explanation:

Step1: Isolate the cube - root term

Divide both sides by 2: $\sqrt[3]{x - 3}=\frac{4}{2}=2$

Step2: Eliminate the cube - root

Cube both sides: $(\sqrt[3]{x - 3})^3=2^3$

Step3: Solve for x

$x-3 = 8$, then $x=8 + 3=11$