y > -2x + 3\ny ≤ x - 2\n(0,0)\n(0,-1)\n(1,1)\n(3,0)

Explanation:

Step1: Check point (0,0) in inequalities

For $y > - 2x+3$, when $x = 0,y=0$, we have $0>-2\times0 + 3$ or $0>3$ (False). For $y\leq x - 2$, when $x = 0,y = 0$, we have $0\leq0 - 2$ or $0\leq - 2$ (False).

Step2: Check point (0,-1) in inequalities

For $y > - 2x+3$, when $x = 0,y=-1$, we have $-1>-2\times0 + 3$ or $-1>3$ (False). For $y\leq x - 2$, when $x = 0,y=-1$, we have $-1\leq0 - 2$ or $-1\leq - 2$ (False).

Step3: Check point (1,1) in inequalities

For $y > - 2x+3$, when $x = 1,y = 1$, we have $1>-2\times1+3$ or $1>1$ (False). For $y\leq x - 2$, when $x = 1,y = 1$, we have $1\leq1 - 2$ or $1\leq - 1$ (False).

Step4: Check point (3,0) in inequalities

For $y > - 2x+3$, when $x = 3,y = 0$, we have $0>-2\times3+3$ or $0>-3$ (True). For $y\leq x - 2$, when $x = 3,y = 0$, we have $0\leq3 - 2$ or $0\leq1$ (True).

Answer:

(3,0)