8 2x + 3y = 10 3x - 10y = 15
8 2x + 3y = 10 3x - 10y = 15
Answer
Explanation:
Step1: Eliminate (x)
Multiply the first equation (2x + 3y = 10) by (3) and the second equation (3x-10y = 15) by (2). $$ \begin{align*} 3\times(2x + 3y)&=3\times10\ 6x+9y&=30\ 2\times(3x - 10y)&=2\times15\ 6x-20y&=30 \end{align*} $$ Subtract the second new - equation from the first new - equation: $$ \begin{align*} (6x + 9y)-(6x-20y)&=30 - 30\ 6x+9y - 6x + 20y&=0\ 29y&=0\ y&=0 \end{align*} $$
Step2: Solve for (x)
Substitute (y = 0) into the first original equation (2x+3y = 10). $$ \begin{align*} 2x+3\times0&=10\ 2x&=10\ x&=5 \end{align*} $$
Answer:
(x = 5,y = 0)