if (f(x)=x^{2}-2x) and (g(x)=6x + 4), for which value of (x) does ((f + g)(x)=0)?\n-4\n-2\n2\n4

Explanation:

Step1: Find (f + g)(x)

$(f + g)(x)=f(x)+g(x)=x^{2}-2x + 6x + 4=x^{2}+4x + 4$

Step2: Set (f + g)(x) equal to 0

$x^{2}+4x + 4 = 0$

Step3: Factor the quadratic equation

$(x + 2)^{2}=0$

Step4: Solve for x

$x+2 = 0$, so $x=-2$

Answer:

-2