if $f(x)=x^{2}-2x$ and $g(x)=6x + 4$, for which value of $x$ does $(f + g)(x)=0$?\n-4\n-2\n2\n4
if $f(x)=x^{2}-2x$ and $g(x)=6x + 4$, for which value of $x$ does $(f + g)(x)=0$?\n-4\n-2\n2\n4
Answer
Explanation:
Step1: Find (f + g)(x)
(f + g)(x)=f(x)+g(x)=(x^{2}-2x)+(6x + 4)=x^{2}+4x + 4
Step2: Set (f + g)(x) equal to 0 and solve
x^{2}+4x + 4 = 0 Since x^{2}+4x + 4=(x + 2)^{2}, we have (x + 2)^{2}=0 Taking the square - root of both sides gives x+2 = 0 x=-2
Answer:
-2