f(x)=2x - 1\ng(x)=7x - 12\nwhat is h(x)=f(x)+g(x)?\n○ h(x)=9x - 13\n○ h(x)=9x - 12\n○ h(x)=-5x + 11\n○…
f(x)=2x - 1\ng(x)=7x - 12\nwhat is h(x)=f(x)+g(x)?\n○ h(x)=9x - 13\n○ h(x)=9x - 12\n○ h(x)=-5x + 11\n○ h(x)=5x - 13
Answer
Explanation:
Step1: Substitute the functions
Given $f(x)=2x - 1$ and $g(x)=7x - 12$, then $h(x)=f(x)+g(x)=(2x - 1)+(7x - 12)$.
Step2: Combine like - terms
Combine the $x$ terms and the constant terms. The $x$ terms are $2x+7x = 9x$, and the constant terms are $-1+( - 12)=-1 - 12=-13$. So $h(x)=9x-13$.
Answer:
$h(x)=9x - 13$