1. $-2x(x + 3)-(x + 1)(x - 2)=$\na. $-x^{2}-7x - 2$.\nb. $-x^{2}+5x + 2$.\nc. $-3x^{2}-7x + 2$.\nd…

1. $-2x(x + 3)-(x + 1)(x - 2)=$\na. $-x^{2}-7x - 2$.\nb. $-x^{2}+5x + 2$.\nc. $-3x^{2}-7x + 2$.\nd. $-3x^{2}-5x + 2$.\ne. $-3x^{2}+5x - 2$.\n2. $\frac{x}{x + 2}-\frac{7}{x - 2}=$\na. $\frac{x - 7}{x + 2}$.\nb. $\frac{x + 7}{x + 2}$.\nc. $\frac{x^{2}-9x - 14}{x^{2}-4}$.\nd. $\frac{x^{2}-9x + 14}{x^{2}-4}$.\ne. $\frac{x - 7}{4}$.\n3. $sqrt3{x^{2}}=$\na. $x^{\frac{2}{3}}$. b. $x^{-3}$. c. $x^{\frac{3}{2}}$. d. $x^{-6}$. e. $x^{6}$.\n4. $\frac{5^{-2}x^{-1}}{x^{4}y^{2}}=$\na. $\frac{1}{25x^{3}y^{2}}$.\nb. $\frac{1}{10x^{5}y^{2}}$.\nc. $\frac{25x^{5}}{y^{2}}$.\nd. $\frac{10}{x^{3}y^{2}}$.\ne. $\frac{1}{25x^{5}y^{2}}$.

1. $-2x(x + 3)-(x + 1)(x - 2)=$\na. $-x^{2}-7x - 2$.\nb. $-x^{2}+5x + 2$.\nc. $-3x^{2}-7x + 2$.\nd. $-3x^{2}-5x + 2$.\ne. $-3x^{2}+5x - 2$.\n2. $\frac{x}{x + 2}-\frac{7}{x - 2}=$\na. $\frac{x - 7}{x + 2}$.\nb. $\frac{x + 7}{x + 2}$.\nc. $\frac{x^{2}-9x - 14}{x^{2}-4}$.\nd. $\frac{x^{2}-9x + 14}{x^{2}-4}$.\ne. $\frac{x - 7}{4}$.\n3. $sqrt3{x^{2}}=$\na. $x^{\frac{2}{3}}$. b. $x^{-3}$. c. $x^{\frac{3}{2}}$. d. $x^{-6}$. e. $x^{6}$.\n4. $\frac{5^{-2}x^{-1}}{x^{4}y^{2}}=$\na. $\frac{1}{25x^{3}y^{2}}$.\nb. $\frac{1}{10x^{5}y^{2}}$.\nc. $\frac{25x^{5}}{y^{2}}$.\nd. $\frac{10}{x^{3}y^{2}}$.\ne. $\frac{1}{25x^{5}y^{2}}$.

Answer

Answer:

  1. d. (-3x^{2}-5x + 2)
  2. c. (\frac{x^{2}-9x - 14}{x^{2}-4})
  3. a. (x^{\frac{2}{3}})
  4. e. (\frac{1}{25x^{5}y^{2}})