2x + 7y = 1\ny = 4x - 8\nis (4, 8) a solution of the system?\nchoose 1 answer:\na yes\nb no
2x + 7y = 1\ny = 4x - 8\nis (4, 8) a solution of the system?\nchoose 1 answer:\na yes\nb no
Answer
Explanation:
Step1: Substitute x = 4 and y = 8 into first - equation
Substitute into $2x + 7y=1$. We get $2\times4 + 7\times8$. $2\times4+7\times8=8 + 56=64\neq1$.
Step2: Check second - equation
Substitute into $y = 4x-8$. We get $4\times4-8$. $4\times4 - 8=16 - 8 = 8$. But since it fails the first equation, we don't need to fully rely on the second - equation result for the overall determination.
Answer:
B. No