if (f(x)=3 - 2x) and (g(x)=\frac{1}{x + 5}), what is the value of ((\frac{f}{g})(8))?\n-169\n-1\n13\n104

if (f(x)=3 - 2x) and (g(x)=\frac{1}{x + 5}), what is the value of ((\frac{f}{g})(8))?\n-169\n-1\n13\n104

if (f(x)=3 - 2x) and (g(x)=\frac{1}{x + 5}), what is the value of ((\frac{f}{g})(8))?\n-169\n-1\n13\n104

Answer

Explanation:

Step1: Find f(8)

Substitute x = 8 into f(x): $f(8)=3 - 2\times8=3 - 16=- 13$

Step2: Find g(8)

Substitute x = 8 into g(x): $g(8)=\frac{1}{8 + 5}=\frac{1}{13}$

Step3: Calculate $(\frac{f}{g})(8)$

$(\frac{f}{g})(8)=\frac{f(8)}{g(8)}=\frac{-13}{\frac{1}{13}}=-13\times13=-169$

Answer:

-169