if (f(x)=3 - 2x) and (g(x)=\frac{1}{x + 5}), what is the value of (left(\frac{f}{g}\right)(8)?\n-169\n-1\n13\…

if (f(x)=3 - 2x) and (g(x)=\frac{1}{x + 5}), what is the value of (left(\frac{f}{g}\right)(8)?\n-169\n-1\n13\n104

if (f(x)=3 - 2x) and (g(x)=\frac{1}{x + 5}), what is the value of (left(\frac{f}{g}\right)(8)?\n-169\n-1\n13\n104

Answer

Explanation:

Step1: Recall the definition of function - division

$\left(\frac{f}{g}\right)(x)=\frac{f(x)}{g(x)}$.

Step2: Substitute $x = 8$ into $f(x)$ and $g(x)$

First, find $f(8)$: $f(8)=3 - 2\times8=3 - 16=- 13$. Then, find $g(8)$: $g(8)=\frac{1}{8 + 5}=\frac{1}{13}$.

Step3: Calculate $\left(\frac{f}{g}\right)(8)$

$\left(\frac{f}{g}\right)(8)=\frac{f(8)}{g(8)}=\frac{-13}{\frac{1}{13}}=-13\times13=-169$.

Answer:

-169