34 katelyn wants to buy a $75.00 skateboard. she has $25.00 saved so far. she mows lawns to make extra money…

34 katelyn wants to buy a $75.00 skateboard. she has $25.00 saved so far. she mows lawns to make extra money and earns $20.00 for each lawn she mows. which inequality can be used to determine the number of lawns, x, she needs to mow to have enough money to buy the skateboard? a 25 + 20x ≤ 75 b 25 + 20x ≥ 75 c 20 + 25x ≤ 75 d 20 + 25x ≥ 75 35 a coach compared the heights of the players on two different teams. the data set is shown in the table below. heights of players on two teams team a player heights (inches) 76 68 73 65 60 63 69 76 team b player heights (inches) 63 73 64 70 70 67 75 62 based on these data, which statement is true? a the mean height of the players on team b is greater than the mean height of the players on team a. b the mean height of the players on team a is greater than the mean height of the players on team b. c the median height of the players on team b is greater than the median height of the players on team a. d the median height of the players on team a is greater than the median height of the players on team b.
Answer
34.
Explanation:
Step1: Analyze the money - making situation
She has $25$ saved and earns $20$ for each lawn $x$ she mows. So the total money she has is $25 + 20x$.
Step2: Determine the inequality
She needs enough money to buy a $75$ - dollar skateboard, so the total money $25+20x$ should be greater than or equal to $75$. The inequality is $25 + 20x\geq75$.
Answer:
B. $25 + 20x\geq75$
35.
Explanation:
Step1: Calculate the mean of Team A
The sum of heights of Team A is $76 + 68+73 + 65+60+63+69+76=550$. The number of players $n = 8$. The mean of Team A, $\bar{x}_A=\frac{550}{8}=68.75$.
Step2: Calculate the mean of Team B
The sum of heights of Team B is $63 + 73+64 + 70+70+67+75+62 = 544$. The number of players $n = 8$. The mean of Team B, $\bar{x}_B=\frac{544}{8}=68$.
Step3: Calculate the median of Team A
Arrange the heights of Team A in ascending - order: $60,63,65,68,69,73,76,76$. The median of Team A (since $n = 8$) is $\frac{68 + 69}{2}=68.5$.
Step4: Calculate the median of Team B
Arrange the heights of Team B in ascending - order: $62,63,64,67,70,70,73,75$. The median of Team B (since $n = 8$) is $\frac{67+70}{2}=68.5$. Since $\bar{x}_A = 68.75$ and $\bar{x}_B=68$, the mean height of the players on Team A is greater than the mean height of the players on Team B.
Answer:
B. The mean height of the players on Team A is greater than the mean height of the players on Team B.