if (r(x)=3x - 1) and (s(x)=2x + 1), which expression is equivalent to (left(\frac{r}{s}\right)(6))?\n(\frac{3…

if (r(x)=3x - 1) and (s(x)=2x + 1), which expression is equivalent to (left(\frac{r}{s}\right)(6))?\n(\frac{3(6)-1}{2(6)+1})\n(\frac{(6)}{2(6)+1})\n(\frac{36 - 1}{26+1})\n(\frac{(6)-1}{(6)+1})

if (r(x)=3x - 1) and (s(x)=2x + 1), which expression is equivalent to (left(\frac{r}{s}\right)(6))?\n(\frac{3(6)-1}{2(6)+1})\n(\frac{(6)}{2(6)+1})\n(\frac{36 - 1}{26+1})\n(\frac{(6)-1}{(6)+1})

Answer

Answer:

A. $\frac{3(6)-1}{2(6)+1}$

Explanation:

Step1: Recall function - quotient rule

The quotient of two functions $r(x)$ and $s(x)$ is defined as $\left(\frac{r}{s}\right)(x)=\frac{r(x)}{s(x)}$, where $s(x)\neq0$.

Step2: Substitute $x = 6$

When we want to find $\left(\frac{r}{s}\right)(6)$, we substitute $x = 6$ into $\frac{r(x)}{s(x)}$. Given $r(x)=3x - 1$ and $s(x)=2x + 1$, we get $\frac{r(6)}{s(6)}=\frac{3(6)-1}{2(6)+1}$.