$-x + 4y = 4$\n\n$-x + 3y = 1$\n\nis $(8, 3)$ a solution of the system?\n\nchoose 1 answer:\n\na yes\n\nb…

$-x + 4y = 4$\n\n$-x + 3y = 1$\n\nis $(8, 3)$ a solution of the system?\n\nchoose 1 answer:\n\na yes\n\nb no\n\nshow calculator

$-x + 4y = 4$\n\n$-x + 3y = 1$\n\nis $(8, 3)$ a solution of the system?\n\nchoose 1 answer:\n\na yes\n\nb no\n\nshow calculator

Answer

Explanation:

Step1: Check first equation

Substitute (x = 8), (y = 3) into (-x + 4y = 4). Left side: (-8 + 4\times3 = -8 + 12 = 4). Right side: (4). So first equation holds.

Step2: Check second equation

Substitute (x = 8), (y = 3) into (-x + 3y = 1). Left side: (-8 + 3\times3 = -8 + 9 = 1). Right side: (1). So second equation holds.

Answer:

A. Yes