(5x^{4}+2x^{2}-15x + 10)div(x + 2)

Explanation:

Step1: Use polynomial long division

$$ \begin{array}{r} 5x^{3}-10x^{2}+22x - 59 \ x + 2\overline{\smash{)}5x^{4}+0x^{3}+2x^{2}-15x + 10} \ \underline{5x^{4}+10x^{3}} \ -10x^{3}+2x^{2} \ \underline{-10x^{3}-20x^{2}} \ 22x^{2}-15x \ \underline{22x^{2}+44x} \ -59x + 10 \ \underline{-59x-118} \ 128 \ \end{array} $$ The quotient is (5x^{3}-10x^{2}+22x - 59) and the remainder is (128).

Answer:

The result of ((5x^{4}+2x^{2}-15x + 10)\div(x + 2)) is (5x^{3}-10x^{2}+22x - 59+\frac{128}{x + 2})