if (f(x)=5x), what is (f^{-1}(x))?\n(f^{-1}(x)= - 5x)\n(f^{-1}(x)=-\frac{1}{5}x)\n(f^{-1}(x)=\frac{1}{5}x)\n(…
if (f(x)=5x), what is (f^{-1}(x))?\n(f^{-1}(x)= - 5x)\n(f^{-1}(x)=-\frac{1}{5}x)\n(f^{-1}(x)=\frac{1}{5}x)\n(f^{-1}(x)=5x)
Answer
Explanation:
Step1: Let $y = f(x)$
$y = 5x$
Step2: Solve for $x$ in terms of $y$
$x=\frac{y}{5}$
Step3: Swap $x$ and $y$ to find the inverse
$f^{-1}(x)=\frac{1}{5}x$
Answer:
$f^{-1}(x)=\frac{1}{5}x$ (corresponding to the option where $f^{-1}(x)=\frac{1}{5}x$)