81. 5,238 ÷ 9\n83. 13,653 ÷ 9\n85. 3 × 11\n86. 2,874 ÷ 3\n89. days from november 13 to january 15\n90. 4 ×…

81. 5,238 ÷ 9\n83. 13,653 ÷ 9\n85. 3 × 11\n86. 2,874 ÷ 3\n89. days from november 13 to january 15\n90. 4 × 862\n93. 1,602 ÷ 9\n95. 6,878 + 1,626\n97. 75 - 28\n98. 4,710 + 2,777\n99. amount spent if the change from $20 was $14.35\n100. 3 quarters, 1 nickel and 1 penny = __ ¢\ndown\n1. 5 × 137\n2. 76 ÷ 4\n3. 3,656 ÷ 8\n4. 752 ÷ 8\n5. 86 - 13\n6. cost of 3 hamburgers at $2.41 each\n7. 37 + 27\n8. minutes in 600

81. 5,238 ÷ 9\n83. 13,653 ÷ 9\n85. 3 × 11\n86. 2,874 ÷ 3\n89. days from november 13 to january 15\n90. 4 × 862\n93. 1,602 ÷ 9\n95. 6,878 + 1,626\n97. 75 - 28\n98. 4,710 + 2,777\n99. amount spent if the change from $20 was $14.35\n100. 3 quarters, 1 nickel and 1 penny = __ ¢\ndown\n1. 5 × 137\n2. 76 ÷ 4\n3. 3,656 ÷ 8\n4. 752 ÷ 8\n5. 86 - 13\n6. cost of 3 hamburgers at $2.41 each\n7. 37 + 27\n8. minutes in 600

Answer

Explanation:

Step1: Solve arithmetic operations

1. $5\times137$

$5\times137 = 685$

2. $76\div4$

$76\div4=\frac{76}{4}=19$

3. $3656\div8$

$3656\div8=\frac{3656}{8}=457$

4. $752\div8$

$752\div8=\frac{752}{8}=94$

5. $86 - 13$

$86-13 = 73$

6. Cost of 3 hamburgers at $2.41$ each

$3\times2.41=7.23$

7. $37 + 27$

$37+27 = 64$

8. Minutes in 600 seconds

Since 1 minute = 60 seconds, $600\div60=\frac{600}{60}=10$ minutes

9. $81.5238\div9$

$81.5238\div9=\frac{81.5238}{9}\approx9.0582$

10. $83.13653\div9$

$83.13653\div9=\frac{83.13653}{9}\approx9.2374$

11. $3\times11$

$3\times11 = 33$

12. $2874\div3$

$2874\div3=\frac{2874}{3}=958$

13. $490\div5$

$490\div5=\frac{490}{5}=98$

14. Number of days from November 13 to January 15

November has 30 days, so from November 13 - November 30, there are $30 - 13=17$ days. December has 31 days. January 1 - January 15 has 15 days. Total days: $17 + 31+15=63$ days

15. $4\times862$

$4\times862 = 3448$

16. $1602\div9$

$1602\div9=\frac{1602}{9}=178$

17. $6878+1626$

$6878 + 1626=8504$

18. $75 - 28$

$75-28 = 47$

19. $4710+2777$

$4710+2777 = 7487$

20. Amount spent if change from $20$ was $14.35$

$20 - 14.35=5.65$

21. 3 quarters, 1 nickel and 1 penny in cents

3 quarters = $3\times25 = 75$ cents, 1 nickel = 5 cents, 1 penny = 1 cent. Total: $75+5 + 1=81$ cents

22. $308+383$

$308+383 = 691$

23. $59+4927$

$59+4927 = 4986$

24. $65+27$

$65+27 = 92$

25. $15+28$

$15+28 = 43$

26. $26.8$ (no operation specified, assume it's just a value)

27. $81$ (no operation specified, assume it's just a value)

28. $30$ (no operation specified, assume it's just a value)

29. $31$ (no operation specified, assume it's just a value)

30. $33$ (no operation specified, assume it's just a value)

31. $3$ (no operation specified, assume it's just a value)

32. $3$ (no operation specified, assume it's just a value)

33. $8$ (no operation specified, assume it's just a value)

Answer:

  1. 685
  2. 19
  3. 457
  4. 94
  5. 73
  6. 7.23
  7. 64
  8. 10
  9. $\approx9.0582$
  10. $\approx9.2374$
  11. 33
  12. 958
  13. 98
  14. 63
  15. 3448
  16. 178
  17. 8504
  18. 47
  19. 7487
  20. 5.65
  21. 81
  22. 691
  23. 4986
  24. 92
  25. 43
  26. 26.8
  27. 81
  28. 30
  29. 31
  30. 33
  31. 3
  32. 3
  33. 8