aaron drew the figure below for a school art project. what is the total area of the figure? use the drop…

Explanation:

Step1: Calculate area of left - rectangle

The left - rectangle has length $l = 4$ inches and width $w=2.75$ inches. Area of a rectangle $A_{1}=l\times w$. So $A_{1}=4\times2.75 = 11$ square inches.

Step2: Calculate area of trapezoid

The trapezoid has height $h = 3$ inches, shorter base $b_{1}=2.75$ inches and longer base $b_{2}=4.25$ inches. Area of a trapezoid $A_{2}=\frac{(b_{1} + b_{2})h}{2}=\frac{(2.75 + 4.25)\times3}{2}=\frac{7\times3}{2}=10.5$ square inches.

Step3: Calculate area of middle - rectangle

The middle - rectangle has length $l = 3$ inches and width $w = 2.75$ inches. Area of a rectangle $A_{3}=l\times w=3\times2.75 = 8.25$ square inches.

Step4: Calculate area of right - rectangle

The right - rectangle has length $l = 3$ inches and width $w = 2$ inches. Area of a rectangle $A_{4}=l\times w=3\times2 = 6$ square inches.

Step5: Calculate area of right - triangle

The right - triangle has base $b = 2$ inches and height $h = 2.5$ inches. Area of a triangle $A_{5}=\frac{1}{2}bh=\frac{1}{2}\times2\times2.5 = 2.5$ square inches.

Step6: Calculate total area

Total area $A=A_{1}+A_{2}+A_{3}+A_{4}+A_{5}=11 + 10.5+8.25+6+2.5=38.25$ square inches.

Answer:

The trapezoid has a height of 3 inches, a shorter base measuring 2.75 inches, and a longer base measuring 4.25 inches. The total area of the entire figure is 38.25 square inches.