what is the absolute value of the complex number -4 - √2i?\n√14\n3√2\n14\n18

Explanation:

Step1: Recall absolute - value formula

For a complex number (z = a+bi), the absolute value (|z|) is given by (|z|=\sqrt{a^{2}+b^{2}}). Here, (a=-4) and (b =-\sqrt{2}).

Step2: Substitute values into formula

[ \begin{align*} |z|&=\sqrt{(-4)^{2}+(-\sqrt{2})^{2}}\ &=\sqrt{16 + 2}\ &=\sqrt{18}\ &=3\sqrt{2} \end{align*} ]

Answer:

B. (3\sqrt{2})