according to the fundamental theorem of algebra, how many roots exist for the polynomial function? (9x +…

according to the fundamental theorem of algebra, how many roots exist for the polynomial function? (9x + 7)(4x + 1)(3x + 4) = 0\n1 root\n3 roots\n4 roots\n9 roots

according to the fundamental theorem of algebra, how many roots exist for the polynomial function? (9x + 7)(4x + 1)(3x + 4) = 0\n1 root\n3 roots\n4 roots\n9 roots

Answer

Answer:

B. 3 roots

Explanation:

Step1: Recall the fundamental theorem

The fundamental theorem of algebra states that the number of roots of a polynomial equation is equal to its degree.

Step2: Analyze the given polynomial

The given polynomial ((9x + 7)(4x + 1)(3x + 4)=0) is a product of three linear factors. When we expand it, the highest - power of (x) will be (x^3) (since (x\times x\times x=x^3) when multiplying the linear terms). So the degree of the polynomial is 3.

Step3: Determine the number of roots

Since the degree of the polynomial is 3, according to the fundamental theorem of algebra, the number of roots is 3.