ad = db and ae = ec. ef = 5 and m∠aed = 32°. m∠ecf = ?°
ad = db and ae = ec. ef = 5 and m∠aed = 32°. m∠ecf = ?°
Answer
Answer:
32
Explanation:
Step1: Identify Midsegments
Since (AD = DB) and (AE = EC), (DE) is the midsegment of (\triangle ABC). By the Midsegment Theorem, (DE \parallel BC).
Step2: Use Alternate Interior Angles
When two parallel lines ((DE \parallel BC)) are cut by a transversal ((AC)), alternate interior angles are equal. So (\angle AED) and (\angle ECF) are alternate interior angles.
Step3: Determine the Angle Measure
Given (m\angle AED = 32^\circ), we conclude (m\angle ECF = m\angle AED = 32^\circ).