what is the additive inverse of the complex number 9 - 4i?\n-9 - 4i\n-9 + 4i\n9 - 4i\n9 + 4i
what is the additive inverse of the complex number 9 - 4i?\n-9 - 4i\n-9 + 4i\n9 - 4i\n9 + 4i
Answer
Explanation:
Step1: Recall additive - inverse definition
The additive inverse of a complex number (a + bi) is (-a - bi) such that ((a + bi)+(-a - bi)=0). For the complex number (z = 9-4i), where (a = 9) and (b=- 4).
Step2: Find the additive inverse
The additive inverse has real - part (-a=-9) and imaginary - part (-b = -(-4)=4). So the additive inverse is (-9 + 4i).
Answer:
B. (-9 + 4i)